Navigation

Concept Review

Integral Calculus

Series and Sequences

1. What Are Sequences and Series?

  • Sequence: A list of numbers in order
    a1,a2,a3,a_1, a_2, a_3, \dots

  • Series: The sum of a sequence
    n=1an\sum_{n=1}^{\infty} a_n


2. Divergence Test (Test for Divergence)

If
limnan0\lim_{n \to \infty} a_n \neq 0
or does not exist → the series diverges

Example

n=1nn+1\sum_{n=1}^{\infty} \frac{n}{n+1}

Solution: limnnn+1=10\lim_{n \to \infty} \frac{n}{n+1} = 1 \neq 0
❌ Diverges


3. Integral Test

If:

  • f(n)=anf(n) = a_n is positive, continuous, decreasing

Then: an and 1f(x)dx\sum a_n \text{ and } \int_1^\infty f(x)\,dx
either both converge or both diverge

Example

n=11n2\sum_{n=1}^{\infty} \frac{1}{n^2}

Solution: 11x2dx=[1x]1=1\int_1^\infty \frac{1}{x^2} dx = \left[-\frac{1}{x}\right]_1^\infty = 1
✅ Converges → Series converges


4. p-Series Test

n=11np\sum_{n=1}^{\infty} \frac{1}{n^p}

  • Converges if p>1p > 1
  • Diverges if p1p \leq 1

Example

n=11n1.5\sum_{n=1}^{\infty} \frac{1}{n^{1.5}}

p=1.5>1p = 1.5 > 1 → ✅ Converges


5. Direct Comparison Test

Compare with a known series:

  • If 0anbn0 \le a_n \le b_n and bn\sum b_n converges → an\sum a_n converges
  • If anbna_n \ge b_n and bn\sum b_n diverges → an\sum a_n diverges

Example

n=11n2+1\sum_{n=1}^{\infty} \frac{1}{n^2 + 1}

Compare: 1n2+11n2\frac{1}{n^2+1} \le \frac{1}{n^2}

Since 1n2\sum \frac{1}{n^2} converges → ✅ Converges


6. Limit Comparison Test

If: limnanbn=c\lim_{n \to \infty} \frac{a_n}{b_n} = c
where 0<c<0 < c < \infty, both series behave the same

Example

n=13n+1n2+2\sum_{n=1}^{\infty} \frac{3n+1}{n^2+2}

Compare with: 1n\frac{1}{n}

Compute: limn3n+1n2+21n=limnn(3n+1)n2+2=3\lim_{n\to\infty} \frac{\frac{3n+1}{n^2+2}}{\frac{1}{n}} = \lim_{n\to\infty} \frac{n(3n+1)}{n^2+2} = 3

Since 1n\sum \frac{1}{n} diverges → ❌ Diverges


7. Ratio Test

Compute: L=limnan+1anL = \lim_{n\to\infty} \left| \frac{a_{n+1}}{a_n} \right|

  • L<1L < 1 → Converges
  • L>1L > 1 → Diverges
  • L=1L = 1 → Inconclusive

Example

n=11n!\sum_{n=1}^{\infty} \frac{1}{n!}

an+1an=1/(n+1)!1/n!=1n+1\frac{a_{n+1}}{a_n} = \frac{1/(n+1)!}{1/n!} = \frac{1}{n+1}

limn1n+1=0<1\lim_{n\to\infty} \frac{1}{n+1} = 0 < 1
✅ Converges


8. Geometric Series

Form: n=0arn\sum_{n=0}^{\infty} ar^n

  • Converges if r<1|r| < 1
  • Sum: a1r\frac{a}{1-r}

Example

n=02(13)n\sum_{n=0}^{\infty} 2\left(\frac{1}{3}\right)^n

a=2a=2, r=13r=\frac{1}{3}

S=2113=223=3S = \frac{2}{1 - \frac{1}{3}} = \frac{2}{\frac{2}{3}} = 3
✅ Converges, sum = 3


9. Alternating Series Test (Leibniz Test)

For: n=1(1)nan\sum_{n=1}^{\infty} (-1)^n a_n

Converges if:

  1. ana_n decreases
  2. limnan=0\lim_{n \to \infty} a_n = 0

Example

n=1(1)nn\sum_{n=1}^{\infty} \frac{(-1)^n}{n}

  • Decreasing ✔
  • Limit = 0 ✔

✅ Converges


Quick Summary

TestWhen to Use
DivergenceFirst check always
Integral1/np1/n^p-like
p-seriesExact form
ComparisonSimilar size
Limit ComparisonComplicated ratios
RatioFactorials, exponentials
Geometricrnr^n pattern
Alternating(1)n(-1)^n present